Factoring Common factors of 520,523 and 525

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Factors of 520,523 and 525

Use the form below to do your conversion, separate numbers by comma.

Factors are

Factors of 520 =1, 2, 4, 5, 8, 10, 13, 20, 26, 40, 52, 65, 104, 130, 260, 520

Factors of 523 =1, 523

Factors of 525 =1, 3, 5, 7, 15, 21, 25, 35, 75, 105, 175, 525

Equivalent to

what goes into 525

what multiplies to 525

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The real common factors of 520,523,525 is 1

Solution

Factors are numbers that can divide without remainder.

Factors of 520

520/1 = 520         gives remainder 0 and so are divisible by 1
520/2 = 260         gives remainder 0 and so are divisible by 2
520/4 = 130         gives remainder 0 and so are divisible by 4
520/5 = 104         gives remainder 0 and so are divisible by 5
520/8 = 65         gives remainder 0 and so are divisible by 8
520/10 = 52         gives remainder 0 and so are divisible by 10
520/13 = 40         gives remainder 0 and so are divisible by 13
520/20 = 26         gives remainder 0 and so are divisible by 20
520/26 = 20         gives remainder 0 and so are divisible by 26
520/40 = 13         gives remainder 0 and so are divisible by 40
520/52 = 10         gives remainder 0 and so are divisible by 52
520/65 = 8         gives remainder 0 and so are divisible by 65
520/104 = 5         gives remainder 0 and so are divisible by 104
520/130 = 4         gives remainder 0 and so are divisible by 130
520/260 = 2         gives remainder 0 and so are divisible by 260
520/520 = 1         gives remainder 0 and so are divisible by 520

Factors of 523

523/1 = 523         gives remainder 0 and so are divisible by 1
523/523 = 1         gives remainder 0 and so are divisible by 523

Factors of 525

525/1 = 525         gives remainder 0 and so are divisible by 1
525/3 = 175         gives remainder 0 and so are divisible by 3
525/5 = 105         gives remainder 0 and so are divisible by 5
525/7 = 75         gives remainder 0 and so are divisible by 7
525/15 = 35         gives remainder 0 and so are divisible by 15
525/21 = 25         gives remainder 0 and so are divisible by 21
525/25 = 21         gives remainder 0 and so are divisible by 25
525/35 = 15         gives remainder 0 and so are divisible by 35
525/75 = 7         gives remainder 0 and so are divisible by 75
525/105 = 5         gives remainder 0 and so are divisible by 105
525/175 = 3         gives remainder 0 and so are divisible by 175
525/525 = 1         gives remainder 0 and so are divisible by 525

Converting to factors of 520,523,525

We get factors of 520,523,525 numbers by finding numbers that can be multiplied together to equal the target number being converted.

This means numbers that can divide 520,523,525 without remainders. So first number to consider is 1 and 520,523,525

Getting factors is done by diving the number with numbers lower to it in value to find the one that will not leave remainder. Numbers that divide without remainders are the factors.

Instructions:

  1. Type the number you want to convert
    Separate more than 1 number with comma.
  2. Click on convert to factor

Other number conversions to consider

520  521  522  523  524  

522  523  524  525  526  

521  522  523  524  525  

Factors are the numbers you multiply to get another number. For instance, the factors of 25 are 5 and 5, because 5×5 = 25. Some numbers have more than one factorization (more than one way of being factored). For instance, 12 can be factored as 1×12, 2×6, or 3×4. A number that can only be factored as 1 times itself is called "prime". The first few primes are 2, 3, 5, 7, 11, and 13. The number 1 is not regarded as a prime, and is usually not included in factorizations, because 1 goes into everything. (The number 1 is a bit boring in this context, so it gets ignored.

By the way, there are some divisibility rules that can help you find the numbers to divide by. There are many divisibility rules, but the simplest to use are these: If the number is even, then it's divisible by 2. If the number's digits sum to a number that's divisible by 3, then the number itself is divisible by 3. If the number ends with a 0 or a 5, then it's divisible by 5.

Of course, if the number is divisible twice by 2, then it's divisible by 4; if it's divisible by 2 and by 3, then it's divisible by 6; and if it's divisible twice by 3 (or if the sum of the digits is divisible by 9), then it's divisible by 9. But since you're finding the factorization, you don't really care about these non-prime divisibility rules. There is a rule for divisibility by 7, but it's complicated enough that it's probably easier to just do the division on your calculator and see if it comes out even.

If you run out of small numbers and you are not done factoring, then keep trying bigger and bigger whole numbers (9, 14, 17, 20, 23, etc) until you find number that can divide without remainder. For example, 13 is a factor of 52 because 13 divides exactly into 52 (52 ÷ 13 = 4 leaving no remainder). The complete list of factors of 52 is: 1, 2, 4, 13, 26, and 52 (all these divide exactly into 52). If your number doesn't divide in, then the only potential divisors are bigger numbers. Since the square of your number is bigger than the number.









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