Factors of 540 and 542
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Solution Factors are numbers that can divide without remainder. Factors of 540 540/1 = 540 gives remainder 0 and so are divisible by 1540/2 = 270 gives remainder 0 and so are divisible by 2 540/3 = 180 gives remainder 0 and so are divisible by 3 540/4 = 135 gives remainder 0 and so are divisible by 4 540/5 = 108 gives remainder 0 and so are divisible by 5 540/6 = 90 gives remainder 0 and so are divisible by 6 540/9 = 60 gives remainder 0 and so are divisible by 9 540/10 = 54 gives remainder 0 and so are divisible by 10 540/12 = 45 gives remainder 0 and so are divisible by 12 540/15 = 36 gives remainder 0 and so are divisible by 15 540/18 = 30 gives remainder 0 and so are divisible by 18 540/20 = 27 gives remainder 0 and so are divisible by 20 540/27 = 20 gives remainder 0 and so are divisible by 27 540/30 = 18 gives remainder 0 and so are divisible by 30 540/36 = 15 gives remainder 0 and so are divisible by 36 540/45 = 12 gives remainder 0 and so are divisible by 45 540/54 = 10 gives remainder 0 and so are divisible by 54 540/60 = 9 gives remainder 0 and so are divisible by 60 540/90 = 6 gives remainder 0 and so are divisible by 90 540/108 = 5 gives remainder 0 and so are divisible by 108 |